What is the value of $\Lambda _m^o$ $(NaCl)$ at $298 \ K$?

Define $\Lambda _m = \frac{\kappa \times 1000}{C}$ where $C$ is concentration in $mol \ L^{-1}$ and $\kappa$ is conductivity in $S \ cm^{-1}$.

Resistance of a conductivity cell at $298 \ K$ for $0.0100 \ M \ KCl$ is $161.8 \ \Omega$. Resistance becomes $190 \ \Omega$ when $0.005 \ M \ NaOH$ solution is filled in this cell. Calculate: $(i)$ cell constant,$(ii)$ specific conductivity for $NaOH$ solution,and $(iii)$ molar conductivity.

For a strong electrolyte,the molar conductivity is given by $\wedge _m = \wedge _m^o - 10 \sqrt{C}$. Calculate $\wedge _m$ at $0.01 \ M$ if its value at $0.16 \ M$ is $200 \ S \ cm^2 \ mol^{-1}$.

The conductivity of $0.02 \ M$ $KCl$ solution is $0.00250 \ \Omega^{-1} \ cm^{-1}$. What is its molar conductivity?

$AgNO_3$ (aq.) was added to an aqueous $KCl$ solution gradually and the conductivity of the solution was measured. The plot of conductance ( $\Lambda$ ) versus the volume of $AgNO_3$ is